Question

como resolver (x^2-3x-4)/(x+1)?

Answer 1

$\displaystyle \sf \frac{x^2-3x-4}{x+1} \\\\\\ \frac{x^2-3x-4+4x-4x}{x+1} \\\\\\ \frac{x^2+x-4x-4}{x+1} \\\\\\ \frac{x(x+1)-4(x+1)}{x+1} \\\\\\ \frac{(x+1)\cdot (x-4)}{x+1} \\\\\\ \huge\boxed{\sf x - 4 }\checkmark$