Question

Como resolver?
Se possível, cálculo pls
:)​

Answer 1

Resposta:

2+i / 4-3i = 2i=4-3i = i1 i=-1

Answer 2

Racionaliza z:

$\frac{2+i}{4-3i}.\frac{4+3i}{4+3i} ==> \frac{8 + 6i +4i + 3i^2}{16 + 9i^2} \\ \\ \frac{8 + 10i + 3(-1)}{16 + 9(-1)} ==> \frac{8 - 3 + 10i}{16 - 9} \\ \\ z = \frac{5 + 10i}{7} \\ \\ z = \frac{5}{7} + \frac{10i}{7} \\ \\ conjugado = \frac{5}{7} - \frac{10i}{7}$