Question

como resolver o calculo de x°+6x-9?

Answer 1

$x^{2} +6-9=0= \Delta= b^{2} -4.a.c= \Delta= 6^{2} -4.1(-9)= \Delta=36+36=72 x^{1} =-6-+ \sqrt{72} /2=3- \sqrt{72}  x^{2} =-6-+ \sqrt{72} /2=3+ \sqrt{72}$