Question

Como resolver na Fórmula??
$x^{2}$-3x+2=42

Answer 1

$x^2-3x+2=42\\ x^2-3x+2-42=0\\ x^2-3x-40=0\\ \Delta=(-3)^2-4.1.(-40)=9+160=169\\ \\ x=\frac{3\pm\sqrt{169}}{2}=\frac{3\pm13}{2}\\ \\ x_1=-5\\ \\ x_2=8$