Question

como resolver esta questão tirando mmc?

Answer 1

Resposta:

ver abaixo

Explicação passo-a-passo:

$\frac{x.(x-2)}{(x+2).(x-2)} +\frac{3.(x+2)}{(x+2).(x-2)}=\frac{1.(x-2).(x+2)}{(x+2).(x-2)}\\\\x^{2} -2x+3x +6=(x-2).(x+2)\\\\x^{2} +x+6=x^{2} -2^{2} \\\\x^{2} -x^{2} +x=-4-6\\\\x=-10$\\\\$mmc=6\\\frac{x}{6}-\frac{3}{6} =\frac{24}{6}+\frac{2.(x-3)}{6}\\\\x-3=4+2x-6\\\\x-2x=4-6+3\\\\-x=1.(-1)\\\\x=-1$\\\\$mmc=6\\\\\frac{2.(x-2)}{6}-\frac{3.(x+3)}{6}=\frac{6.(5+x)}{6}\\\\2x-4-3x-9=30+6x\\\\2x-3x-6x=30+4+9\\\\-7x=43\\\\x=\frac{-43}{7}$