Question

Como resolver essa matriz?​

Answer 1

Explicação passo-a-passo:

$A=\left[\begin{array}{ccc}2&4\\1&5\\0&7\end{array}\right]$ ; $B=\left[\begin{array}{ccc}3&-2\\-1&6\\9&8\end{array}\right]$

$A^{t}$ e $B^{t}$ significam matrizes transpostas.

Matriz transposta é uma matriz resultante da troca ordenadamente de linhas pelas colunas de outra matriz.

$A=\left[\begin{array}{ccc}2&4\\1&5\\0&7\end{array}\right]$  →  $A^{t}=\left[\begin{array}{ccc}2&1&0\\4&5&7\\\end{array}\right]$

$B=\left[\begin{array}{ccc}3&-2\\-1&6\\9&8\end{array}\right]$  →  $B^{t}=\left[\begin{array}{ccc}3&-1&9\\-2&6&8\\\end{array}\right]$

Multiplicação de matrizes: multiplique o número inteiro por cada elemento da matriz.

Soma de matrizes: some todos os elementos correspondentes de uma matriz com a outra, ou seja, some linha com linha e coluna com coluna.

$2$ × $4$ × $\left[\begin{array}{ccc}2&1&0\\4&5&7\\\end{array}\right]+3$ × $\left[\begin{array}{ccc}3&-1&9\\-2&6&8\\\end{array}\right]$

$2$ × $\left[\begin{array}{ccc}4.2&4.1&4.0\\4.4&4.5&4.7\\\end{array}\right]+\left[\begin{array}{ccc}3.3&3.(-1)&3.9\\3.(-2)&3.6&3.8\\\end{array}\right]$

$2$ × $\left[\begin{array}{ccc}8&4&0\\16&20&28\\\end{array}\right]+\left[\begin{array}{ccc}9&-3&27\\-6&18&24\\\end{array}\right]$

$\left[\begin{array}{ccc}2.8&2.4&2.0\\2.16&2.20&2.28\\\end{array}\right]+\left[\begin{array}{ccc}9&-3&27\\-6&18&24\\\end{array}\right]$

$\left[\begin{array}{ccc}16&8&0\\32&40&56\\\end{array}\right]+\left[\begin{array}{ccc}9&-3&27\\-6&18&24\\\end{array}\right]$

$\left[\begin{array}{ccc}16+9&8+(-3)&0+27\\32+(-6)&40+18&56+24\\\end{array}\right]$

$\left[\begin{array}{ccc}25&5&27\\26&58&80\\\end{array}\right]$