Question

como resolver essa equacao do 2° Grau , x²-x/2+1/16=0​

Answer 1

Resposta:

S={1/4}

Explicação passo-a-passo:

x²-x/2+1/16=0​

mmc(16,2)=16

(16x²-8x+1)/16=0/16

16x²-8x+1=0

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~16x^{2}-8x+1=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=16{;}~b=-8~e~c=1\\\\\Delta=(b)^{2}-4(a)(c)=(-8)^{2}-4(16)(1)=64-(64)=0\\\\x^{'}=x^{''}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-8)-\sqrt{0}}{2(16)}=\frac{8-0}{32}=\frac{8\div8}{32\div8}=\frac{1}{4}$