Question

Como resolver as equaçoes:

7(10+3x) - 1x = 32
                 2


2x + 1x = 6
3      4


4y-10+y=18+7y


2x+1 - x-3 = x
  4        5     3

Answer 1

7(10+3x) - 1x = 32  mmc= 2
                 2
14(10+3x) - x = 64
140+42x-x=64
41x=64-140
41x= - 76
x= - 76/41

2x + 1x = 6  mmc=12
3      4
8x+3x=72
11x=72
x=72/11

4y-10+y=18+7y
7y-y-4y= - 10 - 18
2y= - 28
y= - 28/2

y= - 14

2x+1 - x-3 = x   mmc= 60
  4        5     3
15(2x+1) - 12(x-3)= 20x
30x+15-12x+36=20x
20x+12x-30x=15+36
2x=51
x=51/2