Question

como resolver a equacão 2x²+x=1 usando a fórmula de Bhaskara

Answer 1

$2x^2 + x = 1 \\ \\ \\ 2x^2 -x - 1 = 0$



$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

a=2, b=1, c=−1

Δ=b^2−4ac
Δ=(1)2−4*(2)*(−1)
Δ=1+8
Δ=9

$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a} \\ \\ \\ x = \dfrac{-1 \pm \sqrt{9}}{2*2} \\ \\ \\ x = \dfrac{-1 \pm 3}{4} \\ \\ \\ x' = \dfrac{-1 + 3}{4} \\ \\ \\ x' = \dfrac{2}{4} \\ \\ \\ x' = \dfrac{1}{2} \\ \\ \\ x'' = \dfrac{-1 - 3}{4} \\ \\ \\ x'' = \dfrac{-4}{4} \\ \\ \\ x'' = -1$

S = {$\dfrac{1}{2} , \ -1$}