Question

Como resolver a derivada l(x)= 8.cos(8x+6)?

Answer 1

Resposta:

✧ I(x) = 8cos (8x + 6)

✧ I' (x) = d / dx ( 8cos(8x + 6))

✧ I' (x) = 8 . d / dx ( cos (8x + 6))

✧ I' (x) = 8 . d / dg ( cos (g)) d / dx ( 8x + 6)

✧ I' (x) = 8 . ( - sin (g) . d / dx ( 8x + 6 ))

✧ I' (x) = 8 . ( - sin( 8x + 6 ) . 8 )

✦ I' (x) = - 64 sin ( 8x + 6 )

Answer 2

Resposta:

Dada a função $l$ definida por:

$l(x) = 8\cdot cos\left(8x + 6\right),$

calculemos sua derivada.

Vamos utilizar a Regra da Cadeia:

$\frac{\big{dl}}{\big{dx}} = \frac{\big{d}}{\big{dx}}\left[8\cdot cos(8x+6)\right]\\\\= 8 \cdot \frac{\big{d}}{\big{dx}}\left[cos(8x+6)\right]\\\\= 8 \cdot \left[-sin(8x + 6) \right] \cdot \frac{\big{d}}{\big{dx}}\left(8x + 6\right)\\\\= 8 \cdot \left[-sin(8x + 6) \right] \cdot 8\\\\= \boxed{-64 \cdot sin(8x+6)}$