Question

como resolver 3x^+5x=-x-9+2x^​

Answer 1

        $3x^{2}+5x=-x-9+2x^{2}<=>$

$<=>3x^{2}+5x+x+9-2x^{2}=0<=>$

$<=>x^{2}+6x+9=0$

        $x=\frac{-6-\sqrt{6^{2}-4*1*9}}{2*1}$   ∨   $x=\frac{-6+\sqrt{6^{2}-4*1*9}}{2*1}<=>$

$<=>x=\frac{-6-\sqrt{36-36}}{2}$   ∨   $x=\frac{-6+\sqrt{36-36}}{2}<=>$

$<=>x=\frac{-6-\sqrt{0}}{2}$   ∨   $x=\frac{-6+\sqrt{0}}{2}<=>$

$<=>x=\frac{-6-0}{2}$   ∨   $x=\frac{-6+0}{2}<=>$

$<=>x=\frac{-6}{2}$   ∨   $x=\frac{-6}{2}<=>$

$<=>x=-3$   ∨   $x=-3<=>$

$<=>x=-3$