Como que deriva isto
y=x³/2+3x/2
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Olá!
![y=\dfrac{1}{2}x^3+\dfrac{3}{2}x\\\\\dfrac{\text{d}y}{\text{d}x}=\dfrac{1}{2}[3.x^2]+\dfrac{3}{2}[1.x^0]\\\\\dfrac{\text{d}y}{\text{d}x}=\dfrac{3}{2}x^2+\dfrac{3}{2}](https://tex.z-dn.net/?f=y%3D%5Cdfrac%7B1%7D%7B2%7Dx%5E3%2B%5Cdfrac%7B3%7D%7B2%7Dx%5C%5C%5C%5C%5Cdfrac%7B%5Ctext%7Bd%7Dy%7D%7B%5Ctext%7Bd%7Dx%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5B3.x%5E2%5D%2B%5Cdfrac%7B3%7D%7B2%7D%5B1.x%5E0%5D%5C%5C%5C%5C%5Cdfrac%7B%5Ctext%7Bd%7Dy%7D%7B%5Ctext%7Bd%7Dx%7D%3D%5Cdfrac%7B3%7D%7B2%7Dx%5E2%2B%5Cdfrac%7B3%7D%7B2%7D "y=\dfrac{1}{2}x^3+\dfrac{3}{2}x\\\\\dfrac{\text{d}y}{\text{d}x}=\dfrac{1}{2}[3.x^2]+\dfrac{3}{2}[1.x^0]\\\\\dfrac{\text{d}y}{\text{d}x}=\dfrac{3}{2}x^2+\dfrac{3}{2}")
Bons estudos!
Bons estudos!
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