Question

como posso resolver esses cálculos?

3 (3x +2) = 6 (3-x)

5 (x + 1) = 3 (x + 2)

5x + (x + 15) -3 (x + 2) = 0

Answer 1

3(3x+2)=6(3-x)
9x+6=18-6x
9x+6x=-6+18
15x=12
x=12/15
x=4/5

5(x+1)=3(x+2)
5x+5=3x+6
5x-3x=-5+6
2x=1
x=1/2

5x+(x+15)-3(x+2)=0
5x+(x+15)-3x-6=0
6x-3x=-15+6
3x=-9
x=-9/3
x=-2