Question

como faço essa conta de equação exponencial ?
8^3x=^3V32^x:4^x-1

Answer 1

Ola Brenda

8^(3x) = (³√32)^x /(4^(x - 1)

na base 2

8 = 2^3

2^9x = 2^(5x/3)/2^(2x -2)

2^9x = 2^(5x/3 - 2x + 2)

2^9x = 2^(5x/3 -  6x/3 + 6/3)

2^9x = 2^(2 - x/3)

9x = 2 - x/3
27x = 6 - x
28x = 6

x = 6/28 = 3/14

.