Question

Como é que eu resolvo (3n+2) (4n+5) = 0 ?

Answer 1

(3n+2) (4n+5) = 0
12n²+15n+8n+10=0
12n²+23n+10=0
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Encontrando as raizes

Δ=b²-4ac
Δ= 23²-4.12.10
Δ= 529-480
Δ=49

X=-b±√Δ/2a
X= -23±√49/2.12
X= -23±7/24
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X¹= -23+7/24
X¹= -16/24 ÷(4)
X¹=-4/6 ÷(2)
X¹=-2/3
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X²= -23-7/24=-30/14
X²= -23-7/24=-30/24 ÷(3)
X²=-10/8 ÷(2)
X²=-5/4
Espero ter ajudado !!! :-)

Answer 2

(3n + 2). (4n + 5) =0; 3n+2=0; 3n =-2; n'= -2/3; 4n +5 = 0; 4n =-5; n" = -5/4; Resp.: (-2/3 , -5/4)