Question

como derivar e simplificar y= x²+3/5x-4

Answer 1

Oi Elaine :)  Segue 

$y= \frac{x^2+3}{5x-4} \\ \\ y'= \frac{(x^2+3)'(5x-4)-(x^2+3)(5x-4)'}{(5x-4)^2} \\ \\ y'= \frac{2x(5x-4)-(x^2+3)5}{(5x-4)^2} \\ \\ y'= \frac{10x^2-8x-5x^2-15}{(5x-4)^2} \\ \\ y'= \frac{5x^2-8x-15}{(5x-4)^2} \\ \\ y'= \frac{5x^2-8x-15}{(5x-4)^2}$