Question

como calcular para x:
a) log4 x=3,5
b) log8 x=5/3
c) log3 x=5
d) log32 x=0,6

Answer 1

a) log4 x=3,5==> n^35/10 = 4 ==> n^7/2 = 2^2 ==> n= (2^2)^7/2 ==> n = 2^7

b) log8 x=5/3 ==> x^5/3 = 8 ==> x^5/3 = 2^3 ==> x= 2^3(^5/3)==> x = 2^5

c) log3 x=5 ==> x^5 = 3 ==> x = 3^1/5

d) log32 x=0,6 => x^0,6 = 32 => x^6/10 = 2^5 ==> x^3/5 = 2^5 => x = (2^5)^3/5==> x=2^3