Question

Com a Formula De Bhaskara,Resolva As Seguinte Equação x²-15x+36=0

Answer 1

x² - 15x + 36 = 0
a = 1, b = -15, c = 36
Δ = b² - 4 · a · c
Δ = (-15)² - 4 · 1 · 36
Δ = 225 - 144
Δ = 81

x1 = -b +√Δ / 2a
x1 = 15 + √81 / 2 · 1
x1 = 15 + 9 / 2
x1 = 24 / 2
x1 = 12

x2 = -b - √Δ / 2a
x2 = 15 - 9 / 2
x2 = 6 / 2
x2 = 3

Answer 2

delta = b^2 - 4ac
delta = (-15)^2 - 4*1*36
delta = 225 - 144
delta = 81

x' = [ -(-15) + 9 ]/2a = 24/2 = 12
x" = [ -(-15) - 9 ]/ 2s = 6/2 = 3

S = {3 ; 12}