Question

caucule o valor de sen 2π + sen π + sen π/2 + sen π/4

Answer 1

sen 2π = sen 360 = 0
sen π = sen 180 = 0
sen π/2 = sen 90 = 1
sen π/4 = sen 45 = $\frac{\sqrt{2}} {2}$
sen 2π + sen π+ sen π/2 + sen π/4 = 0 + 0 + 1 + $\frac{\sqrt{2}} {2}$ =
1 + $\frac{\sqrt{2}} {2}$