Question

calculeeeeeeeeeeeeeeeee​

Answer 1

Resposta:

$\frac{3+\sqrt{3} }{6}$

Explicação passo a passo:

Calcule:

$\frac{tg^230^\°}{1-tg30\°} =\frac{(\frac{\sqrt{3} }{3})^2 }{1-\frac{\sqrt{3} }{3} }=\frac{\frac{3}{9} }{\frac{3-\sqrt{3} }{3} } =\frac{1}{3} *\frac{3}{3-\sqrt{3} } =\frac{1}{3-\sqrt{3} } =\frac{3+\sqrt{3} }{9-3} =\frac{3+\sqrt{3} }{6}$