Question

Calculé x, nos triángulos abaixo:

Answer 1

a) sen 60 = x/20
(√3)/2 = x/20
2x = 20√3
x = 10√3

b) tg 30° = 2/x

Se tg 30 = (√3)/3, então:

2/x = (√3)/3
√3 • x = 2 • 3
x = 6/√3
x = 2√3

c) cos x = x/6
(√3)/2 = x/6
2x = 6√3
x = (6√3)/2
x = 2√3