Question

calcule
$log_{2}8 =$
$log_{2} 32 =$
$log_{3} 27 =$
$log_{4} 64 =$
$log_{5} 125 =$
$log_{9} 81 =$

Answer 1

Vamos lá

log2(8) = log2(2^3) = 3log2(2) = 3

log2(32) = log(2^5) = 5log2(2) = 5

log3(27) = log3(3^3) = 3log3(3) = 3

log4(64) = log4(4^3) = 3log4(4) = 3

log5(125) = log5(5^3) = 3log5(5) = 3

log9(81) = log(81)/log(9) = log(3^4)/log3(3^2) = 4/2 = 2