Question

calcule senB, tgB, tgB, sendo dado
a)cosB=1/2
b)cosB=2/5
c)cosB=0,96
d)cosB=0,17

Answer 1

a)
sen²B+cos²B=1           sen²B=√1

sen²B+(1/2)²=1            sen B=1

sen²B=1-1/2

sen²B=2-1/2

Answer 2

Resposta:

a) cosB=1/2

sen²B+cos²B=1

sen²B+(1/2)²=1

seb²B=1-1/4

sen²B=3/4

senB= √3/4= √3/ √4= √3/2

senB= √3/2= √3/2* 2/2= √3/2

tgB=senB/cosB

tgB= √3/2/1/2

tgB= √3/2*2/1

tgB= √3

cotgB=1/tgB

cotgB=1/ √3

cotgB=1/ √3* √3/ √3=1/ √3=1/ √3* √3/ √3=1 √3/ √9= √3/3

Explicação passo-a-passo: