Question

Calcule,se existir em R o valor de b+√b²-4ac sendo a=3,b=-7 e c=2

Answer 1

$b + \sqrt{b^2-4ac} = \\ \\ -7+ \sqrt{(-7)^2-4(3)(2)} = \\ \\ -7+ \sqrt{49-24} = \\ \\ -7+ \sqrt{25}= \\ \\ -7 \pm 5 = \\ \\ -7 - 5 = -12 \\ \\ -7+5 = -2$

Answer 2

b+√b²-4ac sendo a=3,b=-7 e c=2

          ________
-7 +/-√(-7)²-4.3.2

          _____
-7 +/-√49-24

          ___
-7 +/-√25

- 7 +/-5

x1 = - 1+5 ==> x1 = + 4

x2 = - 1-5 ==> x2 = - 6