Question

calcule por favor me ajude a responder a b c d por favor

Answer 1

a

( x - 1/2)²

quadrado da diferença

[(x)² - 2 * x * 1/2 + (1/2)² ] =

x² - 2x/2 + 1/4 =

Nota >>>2x/2 = 1xou x ***

x² - x + 1/4 **** resposta

b

( x - 2/3)² =

idem

[ (x)² - 2 * x * (2/3) + (2/3)² ]

x² - (4/3)x + 4/9 **** resposta

nota >> 2 * x * 2/3 = 4x/3 ou (4/3).x ***

c

( y² - 1/4)²

[ (y²)² - 2 * y² * 1/4 + ( 1/4)² ] =

y^4 - (2/4)y² + 1/16 ****

Nota >> 2 * y² * 1/4 = 2y²/4 ou (2/4)y² ***

d

( x/2 - y/2)²

[ (x/2)² - 2 * x/2 * y/2 + ( y/2)² ] =

x²/4 - xy/2 + y²/4 ***

Notas >>>

(x/2)² = x/2 * x/2 = x2/4 ***

2/1 * x/2* y/2 = 2xy /4 = por 2 = 1xy/2 ou xy/2 *****

(y/2)² = y/2 * y/2 = y²/4 ***