Question

calcule
para hoje pf o mais rapido possivel

Answer 1

$d)\\ \\ \frac{2}{5m} -\frac{1}{4m^{2}} =\frac{1}{20m^{3}}$

$e)\\ \\ \frac{2a}{y} +\frac{3a}{2y} -\frac{3a}{5y} =\\ \\ mmc=10y \\ \\ \frac{20a+15a-6a}{10y} =\frac{29a}{10y}$

$f)\\ \\igual~a~anterior$

$g)\\ \\ \frac{2a}{3x} +\frac{a}{4x} -\frac{5a}{6x} =\\ \\ mmc=12x\\ \\ \frac{8a+3a-10a}{12x} =\frac{a}{12x}$

$h)\\ \\ \frac{2x}{y} +\frac{3y}{2x} -\frac{1}{6} =\\ \\ mmc=6xy\\ \\ \frac{12x^{2}+18y^{2}-xy}{6xy}$

$i)\\ \\ \frac{x}{2} +\frac{x+1}{x} =\frac{x^{2}+2(x+1)}{2x} =\frac{x^{2}+2x+2}{2x}$

$j)\\ \\ 1+\frac{1+x}{x^{2}-1} \\ \\ observacao:x^{2} -1=(x+1)(x-1)\\ \\ 1+\frac{1+x}{(x+1)(x-1)} =1+\frac{1}{x-1} =\frac{x-1+1}{x-1} =\frac{x-2}{x-1}$

$k)\\ \\ \frac{2}{x+1} -\frac{x}{x+2} =\\ \\ \frac{(2-x)}{(x+1)(x+2)} =-\frac{1}{x+1}$

$l)\\ \\ \frac{x}{a^{2}+ab} +\frac{x}{a^{2}+ab} =\frac{x+x}{a^{2}+ab} =\frac{2x}{a^{2}+ab}$