Calcule os seguintes limites no infinito:
Anexos:
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a)lim 3x²-2x+1=3.(-oo)²-2(-oo)+1
x->-oo
lim 3.oo+2.oo+1=oo+oo+1=2oo+1=oo
x->-oo
b)lim 5x³-3x²+2x-1=5oo-3oo+2oo-1
x->oo
lim 4oo-1=oo
x->oo
c) lim -3x⁴-3x²-1=-3oo-3oo-1=-6oo-1=-oo
x->-oo
d) lim 5x³+1/x²-2=5x=5oo=oo
x->oo
x->-oo
lim 3.oo+2.oo+1=oo+oo+1=2oo+1=oo
x->-oo
b)lim 5x³-3x²+2x-1=5oo-3oo+2oo-1
x->oo
lim 4oo-1=oo
x->oo
c) lim -3x⁴-3x²-1=-3oo-3oo-1=-6oo-1=-oo
x->-oo
d) lim 5x³+1/x²-2=5x=5oo=oo
x->oo
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