Question

calcule os logaritmos abaixo
log2 na base 512
log 1/4 na base 1/32

Answer 1

log 2     = x    ==> 512^x = 2^1 ==> (2^9)^x = 2^1
    512 

9^x = 1 ==> x =  1/9
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log 1/4 na base 1/32

log 1/4     = x    ==> (1/4)^x = 1/32 ==> (2^-2)^x = 2^-5
    1/32
-2x = - 5(-1) ==> 2x = 5 ==> x = 5/2