Question

Calcule o X e Y nas figuras abaixo:​

Answer 1

a -

$Sen(30^o)=\frac{y}{6}\\\frac{1}{2}=\frac{y}{6}\\2.y=6\\y=\frac{6}{2}\\y=3\\\\Sen(30^o)=\frac{x}{10}\\\frac{1}{2}=\frac{x}{10}\\2.x = 10\\x = \frac{10}{2}\\x = 5$

b -

$Sen(60^o)=\frac{x}{6}\\\frac{\sqrt{3}}{2}=\frac{x}{6}\\2.x = 6.\sqrt{3}\\x = \frac{6.\sqrt{3}}{2}\\x = 3.\sqrt{3}\\\\Cos(60^o)=\frac{y}{6}\\\frac{1}{2}=\frac{y}{6}\\2.y=6\\y = \frac{6}{2}\\y=3$

 Lembrando:

• $Seno =\frac{LadoOposto}{Hipotenusa}$
• $Cosseno=\frac{LadoAdjacente}{Hipotenusa}$

Dúvidas só perguntar!