Calcule o volume do solido:
[Vi essa questão no meu simulado e não faço a menor ideia de como respondê-la]
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Boa tarde Bebeto!
Solução!
O volume do cilindro é dado pela formula!
![r1=2,5\\\\\\
h_{1}=1\\\\\
V_{1}= \pi .(2,5)^{2}.1\\\\\
V_{1}= \pi .6,25.1\\\\\
\boxed{V_{1}= \pi 6,25}\\\\\\\\\
r=1\\\\\
h=5\\\\
V_{2} = \pi .(1)^{2}.5\\\\\\
\boxed{V_{2} = \pi 5}\\\\\\](https://tex.z-dn.net/?f=r1%3D2%2C5%5C%5C%5C%5C%5C%5C%0Ah_%7B1%7D%3D1%5C%5C%5C%5C%5C+%0A%0AV_%7B1%7D%3D+%5Cpi+.%282%2C5%29%5E%7B2%7D.1%5C%5C%5C%5C%5C%0AV_%7B1%7D%3D+%5Cpi+.6%2C25.1%5C%5C%5C%5C%5C%0A%5Cboxed%7BV_%7B1%7D%3D+%5Cpi+6%2C25%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%0Ar%3D1%5C%5C%5C%5C%5C%0Ah%3D5%5C%5C%5C%5C%0A%0AV_%7B2%7D+%3D+%5Cpi+.%281%29%5E%7B2%7D.5%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BV_%7B2%7D+%3D+%5Cpi+5%7D%5C%5C%5C%5C%5C%5C%0A "r1=2,5\\\\\\
h_{1}=1\\\\\
V_{1}= \pi .(2,5)^{2}.1\\\\\
V_{1}= \pi .6,25.1\\\\\
\boxed{V_{1}= \pi 6,25}\\\\\\\\\
r=1\\\\\
h=5\\\\
V_{2} = \pi .(1)^{2}.5\\\\\\
\boxed{V_{2} = \pi 5}\\\\\\")
![V_{total}=V_{1} +V_{2}\\\\\\\\
V_{total}=(\pi 6,25+\pi 5)\\\\\\\
V_{total}=\pi (6,25+5)\\\\\\\
\boxed{V_{total}=\pi (11,25)}\\\\\\\
Ou\\\\\\
V_{total}=3,14 (11,25)\\\\\\\
\boxed{V_{total}=35,32}\\\\\](https://tex.z-dn.net/?f=V_%7Btotal%7D%3DV_%7B1%7D+%2BV_%7B2%7D%5C%5C%5C%5C%5C%5C%5C%5C%0AV_%7Btotal%7D%3D%28%5Cpi+6%2C25%2B%5Cpi+5%29%5C%5C%5C%5C%5C%5C%5C%0AV_%7Btotal%7D%3D%5Cpi+%286%2C25%2B5%29%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BV_%7Btotal%7D%3D%5Cpi+%2811%2C25%29%7D%5C%5C%5C%5C%5C%5C%5C%0AOu%5C%5C%5C%5C%5C%5C%0AV_%7Btotal%7D%3D3%2C14+%2811%2C25%29%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BV_%7Btotal%7D%3D35%2C32%7D%5C%5C%5C%5C%5C%0A "V_{total}=V_{1} +V_{2}\\\\\\\\
V_{total}=(\pi 6,25+\pi 5)\\\\\\\
V_{total}=\pi (6,25+5)\\\\\\\
\boxed{V_{total}=\pi (11,25)}\\\\\\\
Ou\\\\\\
V_{total}=3,14 (11,25)\\\\\\\
\boxed{V_{total}=35,32}\\\\\")
Boa tarde!
Bons estudos!
Solução!
O volume do cilindro é dado pela formula!
Boa tarde!
Bons estudos!
bebetoalves:
Poxa, muito obrigado, agora sim consegui entender! :)
Legal!
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