Question

Calcule o valor de X,utilizando o teorema de Pitágoras

Answer 1

$\mathrm{A.)}\\\\25^2 = 20^2 + x^2\\625 = 400 + x^2\\225 = x^2\\x= 15\\\\\\\mathrm{B.)}\\\\x^2 = 22^2 + 28^2\\x^2 = 484 + 784\\x^2 = 1268\\x = \sqrt{1268} \\\mathrm{C.)}\\\\400^2 = (3x)^2 + (4x)^2\\400^2 = 9x^2 + 16x^2\\400^2 = 25x^2\\\sqrt{400^2} = \sqrt{25x^2}\\400 = 5x\\x = 80$