Question

Calcule o valor de P, sendo P = log3 9+5(2+log2 2)- log10

Answer 1

Olá!!

$P = \: log_{3} \: 9 \: + \: 5(2 + \: log_{2} \: 2 \: ) \: \: - log \: 10 \\ P = \: log_{3} \: {3 }^{2} \: \: + 10 \: + 5log_{2} \: {2}^{1} \: - log \: 10 \: \\ P = \: 2 + 10 + 5.1 - 1 \\ P = 12 + 5 - 1 \\ P = \: 16$
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Abraços!!