Question

Calcule o valor de:


a) onze elevado a menos dois


b) dois elevado a menos seis


Pfvr :((

Answer 1

Explicação passo-a-passo:

a) 11^-2= 1/11^2 = 1/121 ou -121

b) 2^-6= 1/2^6 = 1/64 ou -64

Answer 2

• Logo as respostas das alternativas será:

A) $\sf \dfrac{1}{121}$   B)$\sf \dfrac{1}{64}$

• Nessa atividade temos expoentes negativos,para deixar positivo,teremos que aplicar a formula que é:

${\boxed{\boxed{\begin{array}{rcl}\\&{\sf a^{-n}=\dfrac{1}{a^{n}}}&\\\\\end{array}}}}$

$\bf\large{\underline{\quad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\quad}}$✍

• Agora,aplicamos essa formula

${\boxed{\boxed{\begin{array}{rcl}\\&{\sf 11^{-2}=\dfrac{1}{11^{2}}}&\\\\\end{array}}}}$

$\bf\large{\underline{\quad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\quad}}$✍

• Calculamos:

${\boxed{\boxed{\begin{array}{rcl}&\\&{\sf \dfrac{1}{11^{{2}}}= \dfrac{1}{11}\times\dfrac{1}{11}=\dfrac{1}{121}}&\Longleftarrow\\\\\end{array}}}}$

$\bf\large{\underline{\quad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\quad}}$✍

Faremos a mesma coisa que nós fez

B)

${\boxed{\boxed{\begin{array}{rcl}&\\&{\sf 2^{-6}=\dfrac{1}{2^{6}}}&\\\\\end{array}}}}$

$\bf\large{\underline{\quad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\quad}}$✍

Calculamos:

${\boxed{\boxed{\begin{array}{rcl}&\\&{\sf \dfrac{1}{2^{{6}}}= \dfrac{1}{2}\times\dfrac{1}{2}\times\dfrac{1}{2}\times\dfrac{1}{2}\times\dfrac{1}{2}\times\dfrac{1}{2}=\dfrac{1}{64}}\Longleftarrow\\\\\end{array}}}}$

$\large{\text{\bf Bons~estudos.}}$

$\rm Duvidas?$

$\rm Deixe\:um\:coment\acute{a}rio$ =)