Question

calcule o valor de :
a)log2 512\64
b)Log2 (49x3 \7)
Dados log a=5 , log b = 3 e log c = 2 calcule
LOG (A.B2 \C)

Answer 1

a) log₂ 512/64 = log₂ 512 - log₂ 64 = log₂ 2⁹ - log₂ 2⁶ = 9.log₂ 2 - 6.log₂ 2 = 9.1 - 6.1 = 9 - 6 = 3

b) log₂ (49.3/7) = log₂ 49 + log₂ 3 - log₂ 7 = log₂ 7² + log₂ 3 - log₂ 7 = 2.log₂ 7 log₂ 3 - log₂ 7 = log₂ 7 + log₂ 3

c) log (a.b²/c) = log a + log b² - log c = log a + 2.log b - log c = 5 + 2.3 - 2 = 5 + 6 - 2 = 9