Calcule o valor de: (1+3i)^2
Soluções para a tarefa
Respondido por
1
Boa noite Thayla!
Solução!
![(1+3i)^{2}=(1+3i)\times(1+3i)\\\\\\\
(1+3i+3i+9i^{2})\\\\\\
1+6i+9i^{2}\\\\\\
\boxed{Lembrando: i^{2}=-1}\\\\\\
1+6i+9i^{2}\\\\\\
1+6i+9(-1)\\\\\\
1+6i-9\\\\\
\boxed{6i-8}](https://tex.z-dn.net/?f=%281%2B3i%29%5E%7B2%7D%3D%281%2B3i%29%5Ctimes%281%2B3i%29%5C%5C%5C%5C%5C%5C%5C%0A%281%2B3i%2B3i%2B9i%5E%7B2%7D%29%5C%5C%5C%5C%5C%5C%0A1%2B6i%2B9i%5E%7B2%7D%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BLembrando%3A+i%5E%7B2%7D%3D-1%7D%5C%5C%5C%5C%5C%5C%0A++1%2B6i%2B9i%5E%7B2%7D%5C%5C%5C%5C%5C%5C%0A++1%2B6i%2B9%28-1%29%5C%5C%5C%5C%5C%5C%0A1%2B6i-9%5C%5C%5C%5C%5C%0A%5Cboxed%7B6i-8%7D "(1+3i)^{2}=(1+3i)\times(1+3i)\\\\\\\
(1+3i+3i+9i^{2})\\\\\\
1+6i+9i^{2}\\\\\\
\boxed{Lembrando: i^{2}=-1}\\\\\\
1+6i+9i^{2}\\\\\\
1+6i+9(-1)\\\\\\
1+6i-9\\\\\
\boxed{6i-8}")
Boa noite!
Bons estudos!
Solução!
Boa noite!
Bons estudos!
thaylasilva212:
Obrigada
Perguntas interessantes
Química,
1 ano atrás
Matemática,
1 ano atrás
Matemática,
1 ano atrás
Matemática,
1 ano atrás
Física,
1 ano atrás
Matemática,
1 ano atrás