calcule o numero de termos da p.g (9,3,1,...,1/81)
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a1 = 9
a2= 3
q = 3/9 = 1/3 *****
an = 1/81
n = ?
1/81 = 9/1* (1/3)ⁿ⁻¹
(1/3)ⁿ⁻¹ = 1/81 : 9/1 = 1/81 * 1/9 = 1/ 729 =( 1/3)⁶
( 1/3)ⁿ⁻¹ = ( 1/3)⁶
n - 1 = 6
n = 6 + 1
n = 7 ***
a2= 3
q = 3/9 = 1/3 *****
an = 1/81
n = ?
1/81 = 9/1* (1/3)ⁿ⁻¹
(1/3)ⁿ⁻¹ = 1/81 : 9/1 = 1/81 * 1/9 = 1/ 729 =( 1/3)⁶
( 1/3)ⁿ⁻¹ = ( 1/3)⁶
n - 1 = 6
n = 6 + 1
n = 7 ***
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