Question

calcule o modulo do vetor v=(1,-2,2)

Answer 1

$|v|= \sqrt{1^2+(-2)^2+2^2} = \sqrt{1+4+4} = \sqrt{9} =3$

Answer 2

✅ Depois de ter terminado os cálculos, concluímos que o módulo do vetor dado é:

              $\Large\displaystyle\begin{gathered}\|\vec{v}\| = 3 \end{gathered}$

Seja o vetor:

         $\Large\displaystyle\begin{gathered}\vec{v} = (1, -2, 2) \end{gathered}$

Calculando o módulo do referido vetor:

       $\Large\displaystyle\text{ \begin{gathered}\|\vec{v}\| = \sqrt{1^{2} + (-2)^{2} + 2^{2}} \end{gathered} }$

                $\Large\displaystyle\begin{gathered}= \sqrt{1 + 4 + 4} \end{gathered}$

                $\Large\displaystyle\begin{gathered}= \sqrt{9} \end{gathered}$

                $\Large\displaystyle\begin{gathered} = 3\end{gathered}$

✅ Portanto, o módulo do referido vetor é:

       $\Large\displaystyle\begin{gathered}\|\vec{v}\| = 3 \end{gathered}$

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