Matemática, perguntado por péssimaemmat, 1 ano atrás

calcule o mmc entre
a) mmc (12,16,45)
c) mmc (4,6,9,12)
b) mmc (3,5,8)
d) mmc (2,7,9)

Soluções para a tarefa

Respondido por albertrieben
3
Ola Pessima 

a) mmc(12,16,45)

12 = 2^2*3
16 = 2^4
45 = 3^2*5

mmc = 2^4*3^2*5 = 720 

b) mmc (3,5,8)

mmc = 3*5*8 = 120 

c) mmc (4,6,9,12)

4 = 2^2
6 = 2*3
9 = 3^2
12 = 2^2*3

mmc = 2^2*3^2 = 36 

d) mmc (2,7,9)

mmc = 2*7*9 = 126 



Respondido por Usuário anônimo
3
a) mmc (12,16,45) = 720

12,16,45: 2
6,8,45: 2
3,4,45: 2
3,2,45: 2
3,1,45: 3
1,1,15: 3
1,1,5: 5
--------------------
1,1,1 = 2.2.2.2.3.3.5 = 16.9.5 = 16.45 = 720

"""""""""""""""""""""""""""""""""""""""""
c) mmc (4,6,9,12) = 36

4,6,9,12: 2
2,3,9,6: 2
1,3,9,3: 3
1,1,3,1: 3
-------------------------
1,1,1,1 = 2.2.3.3 = 4.9 = 36
_______________________________________
b) mmc (3,5,8) = 120

3,5,8: 2
3,5,4: 2
3,5,2: 2
3,5,1: 3
1,5,1: 5
----------------
1,1,1 = 2.2.2.3.5 = 8.15 = 120

¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨¨
d) mmc (2,7,9) = 126

2,7,9: 2
1,7,9: 3
1,7,3: 3
1,7,1:7
---------------
1,1,1  = 2.3.3.7 = 2.9.7 = 2.63 = 126
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