Matemática, perguntado por Dulcicarvalho29, 11 meses atrás

Calcule o m.d.c pela decomposiçãosimultânea.(60 e 80), (100,200 e 250),(36 e 90), (425,800 e 950), (108,132 e 80)?

Soluções para a tarefa

Respondido por valterbl
2

Oi...

Calcule o MDC de:

a) (60, 80)

60, 80 | 2

30, 40 | 2

15, 20 | 2

15, 10 | 2

15, 5 | 3

5, 5 | 5

1, 1

MDC = 2 . 2 . 5 = 20

MDC = 20

b) (100, 200, 250)

100, 200, 250 | 2

50, 100, 125 | 2

25, 50, 125 | 2

25, 25, 125 | 5

5, 5, 25 | 5

1, 1, 5 | 5

1, 1, 1

MDC = 2 . 5 . 5 = 50

MDC = 50

c) (36, 90)

36, 90 | 2

18, 45 | 2

9, 45 | 3

3, 15 | 3

1, 5 | 5

1, 1

MDC = 2 . 3 . 3 = 18

MDC = 18

d) (425, 800, 950)

425, 800, 950 | 2

425, 400, 475 | 2

425, 200, 475 | 2

425, 100, 475 | 2

425, 50, 475 | 2

425, 25, 475 | 5

85, 5, 95 | 5

17, 1, 19 | 17

1, 1, 19 | 19

1, 1, 1

MDC = 5 . 5 = 25

MDC = 25

e) 108, 132, 80)

108, 132, 80 | 2

54, 66, 40 | 2

27, 33, 20 | 2

27, 33, 10 | 2

27, 33, 5 | 3

9, 11, 5 | 3

3, 11, 5 | 3

1, 11, 5 | 5

1, 11, 1 | 11

1, 1, 1

MDC = 2 . 2 = 4

MDC = 4

Bons estudos.

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