Question

calcule:
o logaritmo de 4 na base 1/8

Answer 1

$log_{4} \frac{1}{8} \\ \\ 4^{x}= \frac{1}{8} \\ \\ ( 2^{2} )^{x} =\frac{1}{ 2^{3} } \\ \\ 2^{2x}=2^{-3}\\ \\ 2x=-3\\ \\ x= \frac{-3}{2}$

Answer 2

log$\frac{1}{8}$4=x
$x= - \frac{2}{3}$