Question

Calcule o limite, se existir:


lim x^2 - 3x/5x
x -> - infinito

Answer 1

Resposta:

+infinito

Explicação passo-a-passo:

Temos que:

lim x^2 - 3x/5x

x->-inf

lim x^2 - 3/5

x->-inf

lim (x^2). [1 - (3/5)/(1/ x^2)]

x->-inf

lim (x^2). [1 - (3/5)/(1/x)^2]

x->-inf

(-inf)^2. [1 - (3/5).(1/ -inf)^2]

+inf. [1 - (3/5).0] => +inf. [1 - 0] => +inf. 1 => +inf.

Blz?

Abs :)