Question

calcule o lado BC
me ajudem por favor ​

Answer 1

Aplique a lei dos senos.

$\frac{6\sqrt{2}}{sen45} = \frac{x}{sen30}$

$\frac{6\sqrt{2}}{\frac{\sqrt{2}}{2}} = \frac{x}{\frac{1}{2}}$

$\frac{2.6\sqrt{2}}{\sqrt{2}} = 2x$

$\frac{6.2\sqrt{2}}{2\sqrt{2}} = x$

$x = 6$