Question

Calcule o determinante das matrizes

Answer 1

c) (1 3 1)

A=(4 1 0)

(-2 3 -3)

Det A=

1(1.(-3)-0.3)-3.(4.(-3)-0.(-2)) +1(4.3-1.(-2))

1.(-3)-3.(-12)+1.(12+2)

-3+36+14=47

d) (½ ⅔ -1)

P=(0 2 3)

(-1 4 0)

Det P

=½(2.0-3.4)-⅔(0.0-3.(-1)) -1(0.4-2.(-1))

=½(-12)-⅔(3)-1(+2)

= -6-2-2 =-6-4=-10