Question

calcule o comprimento da mediana AM do triangulo cujos vertices são A(0,0) B(3,4) C(4,3) ?

Answer 1

Mesmo procedimento, a questão anterior.

$\frac{3+4}{2} = \frac{7}{2} \\ \\ \frac{4+3}{2} = \frac{7}{2}$

$A (0,0) \\ M( \frac{7}{2} , \frac{7}{2}) \\\\ d(AM) = (x2-x1)^{2} + (y2-y1)^{2} \\\\ d(AM) = \sqrt{( \frac{7}{2} - 0)^{2} + ( \frac{7}{2} - 0)^{2}} \\\\ d(AM) = \sqrt{(\frac{49}{4}) + (\frac{49}{4})} \\\\ d(AM) = \sqrt{\frac{49}{2}$