Question

Calcule o 11º termo da PG($\frac{1}{27\\}$,$\frac{1}{9}$,$\frac{1}{3}$)

Answer 1

$> resolucao \\ \\ \geqslant progressao \: \: geometrica \\ \\ q = \frac{a2}{a1} \\ q = \frac{ \frac{1}{9} }{ \frac{1}{27} } \\ q = \frac{1}{9} \times \frac{27}{1} \\ q = \frac{27}{9} \\ q = 3 \\ \\ \\ \geqslant \: o \: 11 \: termo \: da \: pg \\ \\ \\ an = a1 \times q {}^{n - 1} \\ an = \frac{1}{27} \times 3 {}^{11 - 1} \\ an = \frac{1}{27} \times 3 {}^{10} \\ an = \frac{1}{27} \times 59049 \\ an = \frac{59049}{27} \\ an = 2187 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant$