Question

calcule n! /(n+2)+(n+1)=1 /48

Answer 1

n!/[(n+2)!+(n+1)!]=1/48

n!/[(n+2)(n+1)n!+(n+1)n!]=1/48

1/[(n+2)(n+1)+(n+1)]=1/48

48=n²+3n+2+n+1

n²+4n+3=48

n²+4n-45=0

n'=[-4+(16+180)¹/²]/2=5

n"=[-4-(16+180)¹/²]/2<0, ñ existe fatorial negativo

Resposta { 5 }