Question

calcule k(t) = 10t - 19 com o valor de entrada especificado

a)k(-7)
b)k(0)
c)k(1)
d)k(-2)
e)k(1,9)

Answer 1

k(t) = 10t - 19

k(-7):
k(-7) = 10(-7) -19
k(-7) = -70 - 19
k(-7) = -89


k(0):
k(0) = 10(0) - 19
k(0) = 0 - 19
k(0) = - 19


k(1):
k(1) = 10(1) - 19
k(1) = 10 - 19
k(1) = -9


k(-2):
k(-2) = 10(-2) - 19
k(-2) = -20 - 19
k(-2) = - 39


k(1,9) =
k(1,9) = 10(1,9) - 19
k(1,9) = 19 - 19
k(1,9) = 0