Question

Bom diaa, por favor me ajudem a responder :)
1) Calcule a integral indefinida.

Answer 1

Bom dia Daniela!

Solução!

$\int\limits^6_3 {(1+ x^{4}) } \, dx$

$x+ \dfrac{ x^{5} }{5}+c$

$x+ \dfrac{ x^{5} }{5}=\Bigg|_{3}^{6} = \left (x+\dfrac{ x^{5} }{5} \right )-\left ( x+\dfrac{ x^{5} }{5} \right )$

$x+ \dfrac{ x^{5} }{5}=\Bigg|_{3}^{6} = \left (6+\dfrac{ (6)^{5} }{5} \right )-\left ( 3+\dfrac{ (3)^{5} }{5} \right )$


$x+ \dfrac{ x^{5} }{5}=\Bigg|_{3}^{6} = \left (6+\dfrac{ 7776}{5} \right )-\left ( 3+\dfrac{ 243 }{5} \right )$


$x+ \dfrac{ x^{5} }{5}=\Bigg|_{3}^{6} = \left (30+\dfrac{ 7776}{5} \right )-\left ( 15+\dfrac{ 243 }{5} \right )$


$x+ \dfrac{ x^{5} }{5}=\Bigg|_{3}^{6} = \left (\dfrac{ 7806}{5} \right \left - \dfrac{ 258 }{5} \right )$


$x+ \dfrac{ x^{5} }{5}=\Bigg|_{3}^{6} = \left (\dfrac{ 7548}{5} \right )$



B)

$\int\limits {(y+5y^{3}) } \, dx= \dfrac{y^{2} }{2}+ \dfrac{5y^{4} }{4} +c$



Bom dia!
Bons estudos!