Question

calcule, indicando o resultado sem radical

 

∛40

____ =

∛5 

 

 

√490

_____   =

√10

 

 

√2.√6 =

Answer 1

$a) \frac{\sqrt[3]{2^3.5}}{ \sqrt[3]{5} } = \frac{2 \sqrt[3]{5}}{ \sqrt[3]{5}} = 2. \\ \\ \\ b) \frac{ \sqrt{49.10} }{ \sqrt{10}} = \frac{ \sqrt{7^2.10} }{ \sqrt{10}} = \frac{7 \sqrt{10}}{ \sqrt{10}} = 7 \\ \\ \\ c) \sqrt{12} = \sqrt{2^2.3} = 2\sqrt{3}$ 

;)