Matemática, perguntado por rafaelaburgdurff, 1 ano atrás

calcule e simplifique os resultados quando for possivel (a) 1/2+2/3 (b) 5/6+2/3 (c) 4/5+2/3(d) 9/2-7/4+2/3 (e) 2/5+1/10+1/2(f) 2/7+1/10+3/2 por favor gente e pra hj

Soluções para a tarefa

Respondido por robertocarlos5otivr9
3
a) \text{mmc}(2,3)=6

\dfrac{1}{2}+\dfrac{2}{3}=\dfrac{3\cdot1+2\cdot2}{6}=\dfrac{3+4}{6}=\dfrac{7}{6}

b) \text{mmc}(6,3)=6

\dfrac{5}{6}+\dfrac{2}{3}=\dfrac{1\cdot5+2\cdot2}{6}=\dfrac{5+4}{6}=\dfrac{9}{6}=\dfrac{3}{2}

c) \text{mmc}(5,3)=15

\dfrac{4}{5}+\dfrac{2}{3}=\dfrac{3\cdot4+5\cdot2}{15}=\dfrac{12+10}{15}=\dfrac{22}{15}

d) \text{mmc}(2,4,3)=12

\dfrac{9}{2}-\dfrac{7}{4}+\dfrac{2}{3}=\dfrac{6\cdot9-3\cdot7+4\cdot2}{12}=\dfrac{54-21+8}{12}=\dfrac{41}{12}

e) \text{mmc}(5,10,2)=10

\dfrac{2}{5}+\dfrac{1}{10}+\dfrac{1}{2}=\dfrac{2\cdot2+1\cdot1+5\cdot2}{10}=\dfrac{4+1+5}{10}=\dfrac{10}{10}=1

f) \text{mmc}(7,10,2)=70

\dfrac{2}{7}+\dfrac{1}{10}+\dfrac{3}{2}=\dfrac{10\cdot2+7\cdot1+35\cdot3}{70}=\dfrac{20+7+105}{70}=\dfrac{132}{70}=\dfrac{66}{35}

rafaelaburgdurff: muito obg
robertocarlos5otivr9: por nada ^^
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